Question

Use seperation of variables
(dy/dx) = (y/x) and y = 2 when x = 2

Answer 1

feel free to use it then

Answer 2

\[\int y^{-1}dy=\int x^{-1}dx\]

Answer 3

my teacher went from e^lny = e^lnx+c to y = e^lnx*e^c
can you ehy it is like that please

Answer 4

ehy?

Answer 5

explain why*

Answer 6

you see that this thing ints up into lny = lnx + c right?

Answer 7

yep

Answer 8

the inverse of ln IS e ... it means that they undo each other

Answer 9

e^lny = y

e^(lnx+c) is a bit trickier to notice but its based on exponent rules

b^n * b^m = b^(n+m)


e^(lnx+c) = e^lnx * e^c

=x * e^c

Answer 10

e^c is just some constant so they absorb it into one C

y = x*C

Answer 11

oh! I see it now ty

Answer 12

yep