can anyone explain this to me:

Question

anonymous · Answer

$$\left[\begin{matrix}-3k ^{-3} & \times (mn)^{3} \ p ^{-8} & \end{matrix}\right]$$

anonymous · Answer

x = times. not a variable :)

anonymous · Answer

what kind of explanation are you looking for? It's a matrix right?

anonymous · Answer

i don't think it's a matrix, we're working with exponents now.

anonymous · Answer

other ex we did in class:

anonymous · Answer

$$6bc ^{0}$$ = 6b

anonymous · Answer

Yea that is right but I don't see this thing you mentioned can be solved like that.

anonymous · Answer

we did another one, hold up. it's with fractions too

anonymous · Answer

$$5a ^{-4} / 2c$$

anonymous · Answer

= 5/2a^4c

anonymous · Answer

Is there any fraction in the problem you mentioned

anonymous · Answer

yeah, the " /"

anonymous · Answer

So just move the variables with negative power from numerator to denominator and vice versa.

anonymous · Answer

how would u solve the problem above?

anonymous · Answer

I am assuming problem looks like this 
-3k^-8 x (mn)^2 / p^-8

anonymous · Answer

-3k^-3 x (mn)^3 / p^-8 :)

anonymous · Answer

those equation #'s are so small..

anonymous · Answer

Great. So it should be -3(mn)^3 x p^8 / k^3

anonymous · Answer

why?

anonymous · Answer

anything with a negative power is equivalent to its reciprocal with positive power.
so k^-3 will be 1/k^3 
and
1/p^-8 will be p^-8

anonymous · Answer

what about the -3 ?

anonymous · Answer

the first one* not the exponent

anonymous · Answer

It;s just a number with negative sign it stays where it is.

anonymous · Answer

You only have to look for the negative exponents.

anonymous · Answer

and (mn)^3 ?