A particle moves along the x-axis so that at any time t≥0 its velocity is given by v(t)= t^2In(t+2). What is the acceleration of the particle at time t=6

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anonymous · Answer

is this for homework you get multiple trys on?

anonymous · Answer

yeah its for hw

anonymous · Answer

the answer is 29.453 but idk why

anonymous · Answer

well to find acceleration you need to take the second directive of your position function and plug in your time they give you but im really struggling and cant find the second dirvitie atm

anonymous · Answer

yeah finding the derivative of ln for the product rule is hard

anonymous · Answer

derivative of ln is 1/a which would be 1/(t+2) in this case

anonymous · Answer

thx for the help

anonymous · Answer

its going to be 2ln(t+2)+(2t/t+2))+(((t+2)(2t)-t^2)/(t+2)^2 i belive but i could be wrong ive been up for like 36 hours