Question

Find the equation of the plane through (1,1,1) and containing the line which is the intersection of the planes x-y=2 and y-z=1

Answer 1

This is what i have tried doing:I got the vectors perpendicular to the gives planes, namely: v=i-j and u=j-k, then i took the cross product. This resulant vector is parrallel to the line of intersection. Now i believe i am in a position to write the equation of the plane since i have a vector perpinducalr to the plane and a point

Answer 2

Equaition of plane through intersection of x-y-2=0;y-z-1=0 is
(x-y-2)+a(y-z-1)=0
Put in this (1,1,1) and find a

Answer 3

what would be the "a"

Answer 4

a=-2

Answer 5

okay, then what would be the final eequation of the plane

Answer 6

i dont think that is correct

Answer 7

NO it is correct

Answer 8

okay then what is the final equation of the plane

Answer 9

x-3y+2z=0