sqrt3x+16=x+2 What is the solution set?
\[\sqrt{3x+16} = x+ 2\]If im not wrong..
x = 3
sqrt(3x+16)=x+2 OR sqrt(3x)+16=x+2 ? Cuddlepony -- which one?
(2)^(3x + 16)^(1/2) = (x +2)^(2) = 3x + 16 = x^(2) + 4x + 4 = 0 = x^(2) + x - 12 = (x + 4)(x-3) so you are wrong thus -4 and 3
sorry I messed up notation but yeah I just squared both sides of the equation
to elimanate the radical
How should I know I wouldn't ask a question like this
@Directrix
or you are right and I mis interpreted the question meh
only 3x+16 is the sqrt.
Then the answer's 3.
x=-4 is an extraneous solution. It doesn't work. (Try plugging it in.)
Oh sorry I didnt complete the question by taking the domain
You can't take the square root of [0, -infinity)
did you have to use the quadratic equation?
After you square both sides to clear the radical, you will almost always have a quadratic equation on these kinds of problems.
ok, thanks so much!
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