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Mathematics 13 Online
OpenStudy (anonymous):

x, x+3, 15 obtuse

Directrix (directrix):

The sides and classification of a triangle are given. The length of the longest side is the integer given. What value(s) of x make the triangle?

Directrix (directrix):

--> Sakigirl --> gotta learn those theorems. And, see if the Triangle Inequality Theorem is on that sheet.

OpenStudy (anonymous):

Her theorems are listed as numbers.

Directrix (directrix):

x^2 + (x + 3) ^2 > 15^2 if thr triangle is obtuse. It's all yours.

OpenStudy (anonymous):

factoring?

OpenStudy (anonymous):

I honestly just think I should go for tutoring. I'll just skip this one. I don't get it at all.

Directrix (directrix):

I agree on the tutoring because the theorems are fuzzy and frustration has set in. See if you can do these -- they are a little different but the same concepts. A triangle has sides of the given lengths. Is it acute, right, or obtuse? a) 9, 40, 41 b) 6, 7, 8 c) 7, 8, 11

OpenStudy (anonymous):

a. right b. obtuse c. obtuse

Directrix (directrix):

a) correct because 9^2 + 40^2 = 41^2

Directrix (directrix):

Directrix (directrix):

Let's look at these together.

Directrix (directrix):

c is the longest side.

Directrix (directrix):

c^2 = ... right c^2 < .... acute c^2 > ... obtuse That's how i'm going to remember these theorems.

Directrix (directrix):

b) 8^2 ? 6^2 + 7^2 64 36 + 49 64 ??? 85 64 < 85 Triangle is acute

Directrix (directrix):

7,8,11 11^2 ??? 7^2 + 8^2 121 ??? 113 121 > 113 Triangle obtuse.

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