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OpenStudy (anonymous):
Ok, now how do you use the calculator in find the values of x in the first place?
sam (.sam.):
\[\frac{x}{lnx}>5\]
\[\frac{x}{lnx}-5>0\]
\[\frac{x-5\ln(x)}{\ln(x)}>0\]
Form here, x must be >1
because if x=1, ln(1) from the denominator will be =0 which leads to infinity,
x cannot be negative number because ln(-anything) is infinity, so, x>1 is the answer