Ask your own question, for FREE!
Mathematics 23 Online
OpenStudy (anonymous):

The area of a rectangular athletic field is represented by the expression 49x^2-9z^2 square meters. Write an algebraic expression to represent one possible set of dimensions (in the sense “length times width”) of the athletic field. Include correct units with your solution.

Directrix (directrix):

Do you know how to factor the difference of two squares, say a^2 - b^2?

Directrix (directrix):

Becasue that is all you need to do to 49x^2-9z^2 to get the answer.

OpenStudy (anonymous):

I could not find a common number in the two squares

Directrix (directrix):

There's not one. Look at it as (7x)^2 - (3z)^2 and factor that as the difference of two squares.

Directrix (directrix):

That's why I asked about factoring a^2 - b^2 to see if we needed to start there.

OpenStudy (anonymous):

o ok yea I remember reading that last night I must have for gotten. so basically the answer to this would be (7x)^2-(3z)^2 then how do I figure out the length and the width of the court to make the equation. i'm sorry i am really trying to get this it is alot to take in at one time

Directrix (directrix):

My computer will barely move on this site. I have to write on Word or Wordpad and copy my text here. Do you have that problem?

Directrix (directrix):

Let's factor. Yes, it is a lot to remember but we can still do it.

OpenStudy (anonymous):

no I don't have that problem at all

Directrix (directrix):

Your browser is ?

Directrix (directrix):

(7x)^2-(3z)^2 = ( 7x - 3z ) ( 7x + 3z ) following the a^2 - b^2 pattern of (a-b)(a+b)

OpenStudy (anonymous):

google chrome

OpenStudy (anonymous):

so basicaly after I factor the squares I creat the problem which is (7x-3z) is the length and (7x+3z) is the width therefore my solution to this would be (7x-3z)(7x+3z) square meters is this correct?

Directrix (directrix):

That is my understanding of the problem. Add the units which would be meters.

Directrix (directrix):

The question does say *an* acceptable set of dimensions which caused me to wonder if you were to make up a value of x and z but I don't think that is the case. I would go with the dimensions (7x-3z) meters and (7x + 3z) meters.

OpenStudy (anonymous):

ok thank u so much

Directrix (directrix):

Do you have both Google Chrome and Internet Explorer on your computer or just the one. Glad to help.

OpenStudy (anonymous):

I have both

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!