Question

Find the exponential function f(x)=Ca^x whose graph goes through the points (0,4) and (3,32)

Answer 1

f(x)=4(2^x)

Answer 2

whats a and whats c

Answer 3

just apply the given info\[f(x)=Ca^x\]\[f(0)=Ca^0=C=4\]\[f(3)=4a^3=32\to a^3=8\to a=2\]

Answer 4

Take a look at Turing Test's post.

Answer 5

thanks

Answer 6

can you take a look at two more questions pls

Answer 7

Ok

Answer 8

The graph of the function f(x)=6^(x−8) can be obtained from the graph of
g(x)=6^(x) by shifting the graph of g(x) to the right 8 units

The range of the function f(x) is (A,∞)

what is the value of A?

Answer 9

So, you're asking what the minimum value for the range is?

Answer 10

they want the value of A

Answer 11

I'm assuming that's whats being asked. So in 6^(x-8)...if x equals 8 then the exponent equals zero, right?

Answer 12

And as x gets larger than 8, then the exponent becomes postive and the equation goes to infinity exponentially.

Answer 13

So what happens to the equation when x is smaller than 8? It becomes a negative exponent. And what happens to an exponential function with a negative exponent?

Answer 14

hey i got to go. if you type out the solutions i will be back to see it. thanks for the help

Answer 15

The graph behaves exactly like the exponential function 6^x expect that it is shifted to the right by 8 and so the y intercept is at x=8. Think about what happens to an exponential function as the exponent becomes negative. What value does it approach, but never actually gets to?