Question

need help finding limit of a Sequences equation, Thanks

Answer 1

\[3^{n}/(4^{n+1})\]

Answer 2

hey, can u help me on this one? i just got blasted with that quiz question:

Answer 3

do you know this limit

\[\lim_{n\to\infty}r^n\] where \[|r|<1\]

Answer 4

0

Answer 5

is that same as (-r)^n ?

Answer 6

yes

\[\frac{3^n}{4^{n+1}}=\frac{3^n}{4^n}\frac{1}{4}=\left(\frac{3}{4}\right)^n\frac{1}{4}\]

Answer 7

as long as \[-1<r<1\] then \[r^n\to 0\text{ as }n\to\infty\]

Answer 8

not understanding wat u just did.. but i got it right.... mmmm

Answer 9

u split a 1/4 out, is that legal ?

Answer 10

\[4^{n+1}=4^n\cdot 4^1=4^n\cdot 4\]

Answer 11

yes

Answer 12

never new that law... thanks

Answer 13

what if r is not between -1, 1?

Answer 14

\[a^{x+y}=a^xa^y\]

Answer 15

then it does not converge

Answer 16

well... it converges if r=1

Answer 17

so the teacher had question wrong then

Answer 18

1^n=1 for all ... thus the limit would be 1

Answer 19

your problem dones converge and the limit is zero

Answer 20

*does

Answer 21

since -1<3/4<1

Answer 22

i c, a similar problem but with recursion, u know about cobweb plot?

Answer 23

a(sub 1)=2, a(sub n+1)=(4-(3/a(sub n))), It asked for a cobweb plot, when i drew it, there was no limit but it says show the limit.