Question

Implicit Derivative Question. Problem inside:

Answer 1

\[\sqrt{x}-\sqrt{y}=1\]

Answer 2

\[\frac{1}{2\sqrt{x}}+\frac{1}{2\sqrt{y}}y'=0\] is the first step

Answer 3

(1/2Vx ) - dy/2Vy = 0

Answer 4

then algebra to get
\[y'=\frac{-\sqrt{y}}{\sqrt{x}}\]

Answer 5

oh damn i am off by a minus sign. sorry

Answer 6

Are you sure that there is a negative?

Answer 7

Nevermind, thank you, I got the same thing.

Answer 8

\[\frac{1}{2\sqrt{x}}-\frac{1}{2\sqrt{y}}y'=0\]
\[y'=\frac{\sqrt{y}}{\sqrt{x}}\]

Answer 9

no the minus sign was a mistake on my part. i didn't see the minus sign in the problem

Answer 10

I was a little confused for a second. Thank you for your help!

Answer 11

sorry about that
yw