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If I'm correct about what a minor is, the minor of \(A_{22}\) would be the determinant of the matrix if you removed the second row and second column. In other words, the minor of \(A_{22}\) would then be \[(1*9)-(3*7) = 9-21=-12\]
are minor and cofactor same thing??
Close, but not quite. To get the cofactor, you would then have to multiply your minor by \((-1)^{i+j}\) where \(i, j\) are the indices of the row and column you're removing. In your case, they're both 2, so the cofactor would be \[(-1)^{2+2} * (-12) = (-1)^4 *(-12) = 1*(-12)=-12\]which is indeed the minor, but this is not always the case.
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