Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
help please
OpenStudy (mertsj):
You haven't posted a problem.
OpenStudy (anonymous):
for the equation x^2+kx+14=0. The equation has 2 sollutions when the value of k is ???
OpenStudy (mertsj):
2 real solutions or 2 complex solutions?
OpenStudy (anonymous):
well it says the answer is k>root 56 and k< - root 56 but i need to know how to get it
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mertsj):
discriminant must be greater than 0 so b^2-4ac >0 means k^2-56>0
k^2>56 means k>-sqrt56 or k<-sqrt56
OpenStudy (anonymous):
thats because it has two sollutions??
OpenStudy (mertsj):
Lets take a simpler example. If x^2 =4, then x=2 or x=-2
If x^2<4, x must be less than two or greater than -2 (pick some numbers and try it.)
If x^2 > 4 then x must be greater than 2 or less than -2. Again pick some numbers and try it.
OpenStudy (anonymous):
oh k
OpenStudy (mertsj):
So similarly if k^2 >sqrt56, k would have to be bigger than sqrt56 or less than -sqrt56
Still Need Help?
Join the QuestionCove community and study together with friends!