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Mathematics 21 Online
OpenStudy (anonymous):

anyone know year 11 maths

OpenStudy (anonymous):

help please

OpenStudy (mertsj):

You haven't posted a problem.

OpenStudy (anonymous):

for the equation x^2+kx+14=0. The equation has 2 sollutions when the value of k is ???

OpenStudy (mertsj):

2 real solutions or 2 complex solutions?

OpenStudy (anonymous):

well it says the answer is k>root 56 and k< - root 56 but i need to know how to get it

OpenStudy (mertsj):

discriminant must be greater than 0 so b^2-4ac >0 means k^2-56>0 k^2>56 means k>-sqrt56 or k<-sqrt56

OpenStudy (anonymous):

thats because it has two sollutions??

OpenStudy (mertsj):

Lets take a simpler example. If x^2 =4, then x=2 or x=-2 If x^2<4, x must be less than two or greater than -2 (pick some numbers and try it.) If x^2 > 4 then x must be greater than 2 or less than -2. Again pick some numbers and try it.

OpenStudy (anonymous):

oh k

OpenStudy (mertsj):

So similarly if k^2 >sqrt56, k would have to be bigger than sqrt56 or less than -sqrt56

OpenStudy (anonymous):

yes

hero (hero):

11 year old math or grade 11 math?

OpenStudy (anonymous):

grade

hero (hero):

I guess it doesn't matter anyways. I know both.

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