Find dy/dx, using implicit differentiation.
lnx/y = 7 - x
dx/dy =_____
Compare your answer with the result obtained by first solving for y as a function of x and then taking the derivative.
y=____
dx/dy=_____
stuck on all 3 parts on this problem
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OpenStudy (anonymous):
a little confused
is this
\[\ln(\frac{x}{y})\] or
\[\frac{\ln(x)}{y}\]
OpenStudy (anonymous):
the 2nd one ln(x)/y
OpenStudy (anonymous):
then quotient rule for this one
OpenStudy (anonymous):
\[\frac{y\times \frac{1}{x}-\ln(x)y'}{y^2}=-1\]
OpenStudy (anonymous):
\[\frac{y}{x}-\ln(x)y'=-y^2\]
\[-\ln(x)y'=-y^2-\frac{x}{y}\]
\[y'=\frac{y^2}{\ln(x)}+\frac{x}{y\ln(x)}\] if my algebra is right
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OpenStudy (anonymous):
kk so the first thing you gave me was the dy/dx= correct?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
its not taking it for an answer :(
OpenStudy (rogue):
You switched up your x/y's Sat. It should be\[y'=\frac{y^2}{\ln(x)}+\frac{y}{x\ln(x)}\]