Question

f(x)=(x-7)^2-48
a: determine how the para opens and why?
b: find the vertex
c. find the y-intercepts
d: find the x-intercepts

Answer 1

directoion and opening depends on value of A
so it is positive - it opens up. if negative opens down

Answer 2

standard vertex form is:
f(x) = a(x-h)^2+k with vertex at h,k

Answer 3

h = 7 k = -48
so vertex is 7,-48

Answer 4

find x interceptss by setting y = 0
find y intercepts by ssetting x = 0

so what do you think the x and y intercepts are?

Answer 5

We have
\[f(x)=(x-7)^2-48\]
Standard Parabola
\[y=a(x-h)^2+k\]
here a=1 and positive, so it'll open up
b) vertex is (h,k)
h=7 k=-48
so(7, -48)
c) x-intercept put y=0
d) for y-intercept put x=0

Answer 6

thinking...

Answer 7

k

Answer 8

i have noooo idea. we just went over this material last night in class.sooo....

Answer 9

u are looking for the value of y when x =0

so plug in 0 for x

Answer 10

O

Answer 11

so the formula would read (0-7)^2 -48?

Answer 12

yes, so y = ?

Answer 13

1

Answer 14

yes that is your y intercepy. great job

Answer 15

so now we must put 0 into for y and solve for x

Answer 16

ok. i will solve

Answer 17

yes fyi there are two x intercepts

Answer 18

so do i put the whole problem to zero

Answer 19

yes

Answer 20

97