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use sum of a geometric series to find the sum of the first 10 terms of this sequence an=27(0.1)^(n-1)
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30
\[27\times \frac{1-.1^{10}}{1-.1}\]
How did you use sum of a geometric series @PROSS
which is fact is almost exactly 30
ignore the \[.1^{10}=.0000000001\] and you get \[27\times \frac{1}{.9}=27\times \frac{1}{\frac{9}{10}}=27\times \frac{10}{9}=30\]
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use the formula saellite73 gives for an analytic approach. You can check your answer with a calculator.... sum(seq(Y1,x,1,10)) Where Y1=27(0.1)^(x-1)
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