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What is the PH of a .0041 M Mg(OH)2 solution?
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Whenever 1 mole of magnesium hydroxide dissolves, it yields 2 moles of hydroxide. This means that the hydroxide concentration is twice that of the concentration of the original compound once it is dissolved. \[[OH^-]=0.0041*2=0.0082M\]From this, we can calculate the pOH...\[pOH=-\log[OH^-]=2.086\]And since...\[pH=14-pOH=14-2.086=11.91\]
but why can you say that when it's a weak base?
Weak bases don't dissociate completely. Magnesium hydroxide is a strong base, so all of it ionizes in Mg2+ and hydroxides.
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