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Mathematics 21 Online
sam (.sam.):

Who knows how to find the equation from this graph?

sam (.sam.):

OpenStudy (jamesj):

Assume it is a quadratic. Then from the graph, you can read off the roots: call them a and b. Then the function is f(x) = C(x-a)(x-b) You can then use the maximum of the function to find C. Make sense?

OpenStudy (dape):

Looks like a parabola. The vertex is at (0.6, 2800), so it's shifted .6 along x and 2800 along y. We could try to find something on the form \[ y = c(x-0.6)^2+2800 \] It looks like it goes through the origin, so let's choose c so this happens \[ 0 = c(0-0.6)^2+2800 \\ c = -2800/0.6^2 \approx -7778 \] The equation for the graph is approximately \[ y = -7778(x-0.6)^2+2800 \]

OpenStudy (jamesj):

That's another way to do it.

OpenStudy (anonymous):

what dape said.

OpenStudy (anonymous):

In general equation is given by \( (x-\alpha)^2 = 4a(y-\beta) \)

OpenStudy (anonymous):

vertex at \(\alpha, \beta \) and 4a is the latex rectum

OpenStudy (jamesj):

latex rectum? I'm pretty confident you could never use that term with a Western high school student.

OpenStudy (anonymous):

Latus Rectum*

OpenStudy (jamesj):

Even so. There's more than one way to skin this cat.

OpenStudy (anonymous):

I agree James.

OpenStudy (anonymous):

Do you delete my comment? :O

sam (.sam.):

Is f(x) = C(x-a)(x-b) in "completing the square" form?

OpenStudy (anonymous):

F= -3333t^2 + 3999.6 t http://www.wolframalpha.com/input/?i=-3333x^2%2B3999.6x

sam (.sam.):

but from @dape it looks like "completing the square" form, but nevermind , thanks :D

OpenStudy (anonymous):

Do you need my working?

sam (.sam.):

nevermind I know how to solve basic math, :D

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