If f(2) = 3 and f'(2)=-1 find an equation of the tangent line when x = 2. How would I start this??
use the point slope formula \[y-y_1=m(x-x_1)\] with \[x_1=2,y_1=3, m=-1\]
ahh, thank you. i got y=5-x?
i didn't do it
\[y-3=-(x-2)\] \[y-3=-x+2\] \[y=-x+5\] yup
You need to learn order your equation by variable
thank youu! your explanation was very helpful!
the form is y = mx + b
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:) thanks
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I agree with Chlorophyll even though AP calculus will give credit for the other formula. They will even award credit if you just substitute and do not simplify
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