If f(2) = 3 and f'(2)=-1 find an equation of the tangent line when x = 2. How would I start this??
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OpenStudy (anonymous):
use the point slope formula
\[y-y_1=m(x-x_1)\] with
\[x_1=2,y_1=3, m=-1\]
OpenStudy (anonymous):
ahh, thank you. i got y=5-x?
OpenStudy (anonymous):
i didn't do it
OpenStudy (anonymous):
\[y-3=-(x-2)\]
\[y-3=-x+2\]
\[y=-x+5\] yup
OpenStudy (anonymous):
You need to learn order your equation by variable
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OpenStudy (anonymous):
thank youu! your explanation was very helpful!
OpenStudy (anonymous):
the form is y = mx + b
OpenStudy (anonymous):
@Quyen do like that to mention the right person!
OpenStudy (anonymous):
There're so many great solver here, as long as you wish to learn, you'll be better in no time :) Now back to work !
OpenStudy (anonymous):
:) thanks
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OpenStudy (anonymous):
You can post whole day whole night here, learning for FREE :)
OpenStudy (anonymous):
it's awesome!
OpenStudy (precal):
I agree with Chlorophyll
even though AP calculus will give credit for the other formula.
They will even award credit if you just substitute and do not simplify