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Evaluate the following integral if it is convergent.
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\[\int\limits_0^{\infty}e^{-8x}dx=\lim_{\xi \rightarrow \infty} \int\limits_0^{\xi}e^{-8x}dx=\frac{-1}{8} \lim_{\xi \rightarrow \infty}e^{-8x}|_0^{\xi}=\frac{-1}{8}\lim_{\xi \rightarrow \infty} \left[ e^{-8 \xi}-1\right]=\frac{1}{8}\]
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