In triangle ABC, BC = 8, CA = 10, and AB = 12. If M is the midpoint of CA, and BP bisects angle B, find MP.
is therea picturre with this? this is a simple triangle but clarity needs to be on where the points are located,
No, that its the only information given
that is*
i think it is 3 - this the notion that P is located inside the triangle
How did you get your answer? Can you please explain?
what level math is this so I can know what you should have been taught thus far
high school geometry, learning about ratio and proportions and parts of similar triangles
are you even there?
yes
Wow
What have you been doing all this time? lol
i am thinking of how to do this
I don't think the picture right about point P
Bisect angle does NOT divide opposite side evenly!
i have this uncanny urge to use coordinate geometry to place this triangle on a plane and find equations until something relevant happens
You're way too .. hold on, I'm busy
I'm back! I'm thinking of applying the golden ratio rule because it's not right triangle!
M(16.5, sqrt(43.25)/2) this seems like a lot more than i would expect in geometry perhaps it was not meant to be... golden ratio rule? this is news to me
It's a rule applies for bisect angle!
Very interesting, I learn it from solving recent several geometry problems
a/b = (a + b)/a
You should check out the bisect angle to see illustrated picture!
Since AC is divided into half MC and MA, then the bisect angle line divides MC into PC and PM
In other thought: 8/ x = 12/ ( 10 -x) 12x = 80 - 8x ->20x = 80 => x = 4 ( AP) then 10 - x = 6 ( BP) Thus PM = PB - BM = 6 - 5 = 1
@AccessDenied check it out!
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