Question

What is the 19th term of the arithmetic sequence 14, 22, 30, … ?

Answer 1

14+18 \times 8 = 14 + 144 = 158

Answer 2

\[ 14+18 \times 8 = 14 + 144 = 158 \]

Answer 3

6+8x

where x is the term.

Answer 4

6+8(19)

6+152

158

Answer 5

The 19th term is therefor 158 :)

Answer 6

@madscientist101: Can you explain?

Answer 7

thank you!! totally diff than how my teacher showed me haha your way is easier lol

Answer 8

*6+8x @madscientist101

Answer 9

that's what I wrote FFM 6+8x

Answer 10

\[T _{n}=a+(n-1)d\]
a=14
\[T _{2}=a+(2-1)d=22\]
a+d=22

d=22-14=8

\[T _{19}=14+(19-1)8=158\]

Answer 11

Okay, so you go 1 term back and find the 20th term instead of 19th right? @madscientist101

Answer 12

The difference between each term is 8.

It starts with 14

so it must be 14+8(x-1)... because the you don't want the 14 to be counted as the first term.. although it is...

14+8(x-1)
= 14+8x-8
=6+8x

@Foolformath

Answer 13

lol nice Mad :)

Answer 14

lol yup