how much work did the movers do (horizontally) pushing a 160-kg crate 10.3 m across a rough floor without acceleration, if the effective coefficient of friction was 0.50?

Question

anonymous · Answer

Work = F*d,  the force due to friction is the force on the object perpindicular to the surface of friction (gravity acting on the box) times the coefficient of friction
If the box is not accelerating, the force due to horizontal motion is 0, F=m*a where a=0, so the only force done on the box is friction, which is 160kg*9.8m/s^2*(.5) = 784N
W=F*d => 784N*10.3m = 8075.2 N-m

anonymous · Answer

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