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A circle with the longest chord of 8 has the same areea as an equilateral triangle with side x. What is the height of that triangle. Explanations please - thanks :)
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i know the diam is 8 a = 16*3.14 = 50.24
so area of triangle is equal ot 50.24, right?
Longest chord is the diameter, so r=4 Area of circle = area of triangle \[\pi r ^{2}=\frac{\sqrt{3}}{4}(abc)^{\frac{2}{3}}\] \[\pi r ^{2}=\frac{\sqrt{3}}{4}(x ^{3})^{\frac{2}{3}}\] \[\pi r ^{2}=\frac{\sqrt{3}}{4}(x ^{2})\] x=10.77|dw:1330836329847:dw| h could be 9.31
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