Question

find the length of the curve using integration: 3y=2(x^2+1)^3/2 from x=0 to x=3 ans. 21. I need solution.. please help. thanks:))

Answer 1

\[2/3 \int\limits_{0}^{3} (x ^{2}+1)^{3/2}dx\]
\[=2/3 * 2/5 \left[ (1/2x)(x ^{2}+1)^{5/2} \right]_{0}^{3}\]
\[=4/15\left[ (1/6)(3 ^{2}+1)^{5/2} \right] \]
\[=2(10)^{5/2}/45 \]

not sure for the answer sorry

Answer 2

Thanks

Answer 3

l=int(from 0 to 3 ) {sqrt(1+4x^2(x^2+1))} dx
solving this u would get the answer as 21.