Question

y^2-9/y ÷ y+3/y+9

Answer 1

y^2 -9/y *(y+9)/(y+3)

Answer 2

oh this gets messy

Answer 3

na it division not multiplication

Answer 4

you're solving for y though, right?

Answer 5

no just trying to simplify

Answer 6

Not solving for y, but simplifying

Answer 7

(y^2+6y-27)/y

Answer 8

is that the right answer

Answer 9

looks right

Answer 10

Sorry, but do you mean (y^2-9/y) ÷ y+3/y+9 ?

Answer 11

yea

Answer 12

b/c then that would be (y^2-9/y) * (y+9)/(y+3)

Answer 13

technically yes

Answer 14

(y^2+6y-27)/y
would that be the right answer

Answer 15

well what I keep staring at is (y^3 +9y^2 -9y -81)/(y^2 + 3y)

Answer 16

Do you have an image of the original question?

Answer 17

brinethery, you forgot to cancel (y+3)

Answer 18

I don't need to show you do I?

Answer 19

That's why I needed to see an image of the original question. A lot of times when people type these questions out, the order is wrong.

Answer 20

Okay I think I was thrown off by the order here. I'm guessing he means: (y^2-9)/y * (y+9)/(y+3)

Answer 21

b/c then you could factor and cancel out (y+3)

Answer 22

Peterson, pleeease make friends with parentheses.