Question

what is the derivative of ln(x^2) ??? and why???

Answer 1

2/x

Answer 2

what happens to ln?

Answer 3

ln(x^2) = 2ln(x) -> 2/x

Answer 4

it derives

Answer 5

ahhh i see

Answer 6

then how do u find the derivative of (lnx)^4??

Answer 7

do u put 4 in front of lnx ??

Answer 8

\[\lim_{h\to o}\frac{ln(x+h)-ln(x)}{h}\]

\[\lim_{h\to o}\frac{ln(\frac{x+h}{x})}{h}\]

\[\lim_{h\to o}\frac{1}{h}ln(1+\frac{h}{x})\]

\[\lim_{h\to o}\ ln(1+\frac{h}{x})^{1/h}\]
you never really do the first principles afterwards do ya ...

Answer 9

when you learn the power rule x^4; you do, 4x^3

the power rule should be taught as functions instead ....

Answer 10

but im looking for derivative not limits

Answer 11

(f(x))^4 = 4(f(x))^3 * f'(x)

Answer 12

derivatives ARE limits .....

Answer 13

the rules for derivatives are the result of taking their limits ....

Answer 14

ohh

Answer 15

what happens to ln in that problem?

Answer 16

it pops out as a chain rule

Answer 17

(ln(x))^4 -> 4(ln(x))^3 * ln'(x)

Answer 18

dont u divide the problem by 3 cuz of the exponent?

Answer 19

i dont see why you would have to make up new rules that have no bearing on the problem

Answer 20

when we integrate we divide by the exponent; when we take the derivative we mutliply by the exponent

Answer 21

yea thats what im saying didnt we just integrate?

Answer 22

you asked: "then how do u find the derivative of (lnx)^4?? "

Answer 23

so tell me, are we integrating or taking a derivative?

Answer 24

ohh oops

Answer 25

i got the answer thx