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A certain spring obeys hooke's law and requires a force of 10N to stretch it 8cm beyond it's natural length. How much work would be done in stretching the spring from it's natural length to 12cm beyond it's natural length?
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F = -kx. So you have k as a constant, that takes/ 10N to get 8cm, what = percentage of force would it take to get 8cm/10N = 12cm/xN.
The answer is 90N/cm if that helps
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