Simplify completely (x^2+x-12)/(x^2-x-20)÷(3x^2-24+45)/(12x^2-48x-60)
i got 4(x+1)/(x-5)?
help?
(x^(2)+x-12)/(x^(2)-x-20){(3x^(2)-24+45)/(12x^(2)-48x-60) ((x+4)(x-3))/(x^(2)-x-20)*(12x^(2)-48x-60)/(3x^(2)-24+45) ((x+4)(x-3))/((x+4)(x-5))*(12x^(2)-48x-60)/(3x^(2)-24+45) (x-3)/(x-5)*(12x^(2)-48x-60)/(3x^(2)-24+45) (x-3)/(x-5) * (12x^(2)-48x-60)/(3x^(2)+21) (x-3)/(x-5) * (12(x^(2)-4x-5))/(3x^(2)+21) (x-3)/(x-5) * (12(x+1)(x-5))/(3x^(2)+21) (x-3)/(x-5) * 12(x+1)(x-5))/(3(x^(2)+7)) (x-3)/(x-5) * 4(x+1)(x-5)/(x^(2)+7) (x-3) * 4(x+1)/(x^(2)+7) 4(x-3)(x+1)/(x^(2)+7)
its multiple choice A- (x-5)/4(x+1) B- (x+1)/8(x-5) C-4(x+1)/(x-5) D-8(x-5)/(x+1)
I'm sorry. It's You're correct. It's C
(: what about this one
(x^2-4x+4)/(x^2+10x+25) * (x+5)/(x^2+3x-10)
(x-2)/(x+5)^2
x-2/(x+5)^2
(x^2-100)/(x^2+2x-120) ÷ (6x+60)/(x-2)?
o.0 i dont understand how you can do it this fast
sorry, x+10/x+12
x^2-100 = (x+10)(x-10) x^2+2x-120= (x+12)(x-10) ~~ I have a trick to get this fast
Multiple choice again x-1/6(x+6) x-2/6(x+10) x-2/6(x+12) x-1/3(x+12)
Oh, Ok. Sorry. I only did the first part.
x-2/6(x+12)
one more question (x^2+4x-5)/5x^2-8x+3) * (20x-12)/x^2-6x-55) A) 4/x+5 B)4(x-1)/x+5 C) 4/x-11 D)4(x+5)/x-11
C) 4/x-11
Hope you got it :)
Thank you so much for all your help I'm sure ill be back haha
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