If the constant force is applied over a given distance D, along the path of the particle, then the _____ of the particle will increase by FD.
By the Work-Energy theorem, the change in energy of a particle is equal to the work done on the particle. The work done on the particle is the product of the force, F, over the distance, D. Therefore the answer is _______
Speed?
The force does work on the particle. The work, W, that it does on the particle is W = FD By the Work-Energy Theorem, the change of energy of a particle is equal to the work done on it. Hence if this particle has work W = FD done on it, it's energy also changes by the amount FD.
indeed thanks James
For example, if I push a car initially at rest (speed = 0) with a force of F = 1000 N and the car moves a distance of D = 2 meters, then the amount of work I have done on the car is W = FD = (1000)(2) = 2,000 J How does that change in energy level of the car manifest itself? Mostly in the kinetic energy the car now has; i.e., it has non-zero speed.
Notice by the way that if I push the car and **it does not move at all**, then D = 0 and the work I have done is W = FD = 0 This is consistent with the fact that the speed remains zero. I.e., the car has not gained any kinetic energy.
Thanks that helped me a lot and thanks for the quick reply
sure thing
by the conservation of energy ,increase in kinetic energy=total workdone =FD
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