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how do I integrate: ln((x+2)/(x+1)) ?
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use ln( a/b) = ln(a) - ln(b) to break up the problem
I went from that to the equation I have written above.
why would you combine it to make it harder? phi is right, split it up
integration by parts. \[\int\limits u dv= u v- \int\limits v du\] for the 1st integral ln(x+2) dx u= ln(x+2) dv = dx
now find du = d/dx ln(x+2) = 1/(x+2) dx and v = integral dx = x
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can you finish?
No I cant
http://openstudy.com/users/borgerkrig#/updates/4f565507e4b0862cfd074d0b Can you please check this link. Maybe my question seems out of the blue, because it's connected to the question in the link.
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