Question

solve: (3x^2-7x-20)(2x-5)=0

Answer 1

(3x^2-7x-20)(2x-5)=0

Factor: (3x^2-7x-20)

Answer 2

(x-4) (3x + 5) (2x - 5) = 0

x-4 = 0 and x = 4
3x +5 = 0 and x = -5/3
2x - 5 = 0 and x = 5/2

Check my work.

Answer 3

(3x^2-7x-20)(2x-5)=0
factorize it
=(3x^2-12x+5x-20)(2x-5)=0
=(3x(x-4)+5(x-4))(2x-5)=0
=(x-4)(3x+5)(2x-5)=0 now when x-4=0,x=4
when 3x+5=0 then x=-5/3
and when 2x-5=0, x=5/2