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integrate it:dx/(2cosec.x-sin.x)
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\[\int\limits_{?}^{?} [1/ (cosec(x) -\sin(x) ]dx\]
is this the correct equation /?
yes
first convert the cosec to 1 / cosx
sorry 1/ sin x
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\[dx \div(2coces.x-\sin.x)\]
then multiply so you will get (1 - sin^2 x)/Sin x
then
then 1 - sin^2 x = co^2 x
so you will end up with cos^2x /sinx
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the end integration will be some thing like \[\int\limits_{?}^{?} ( \cos^2x ) / \sin x dx\]
which can solved easily after that
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