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Mathematics 23 Online
OpenStudy (anonymous):

How do you find the domain and range of a function? How do you find the domain and range of a function algebraically without a graph? Please don't give me an easy example and solve it. Instead what method should I use to get a reliable answer every time? My textbook finds it out using graphs. But no calculators are allowed at all in the exam, and I wouldn't really have the time to plot difficult ones anyway. Any help would be appreciated.

OpenStudy (anonymous):

domain = what x values can exist range = what y values can exist

OpenStudy (anonymous):

if you give me an equation that you want worked out i wll do so for you

OpenStudy (anonymous):

Ok here we go \[\sqrt{-x^2 - x + 6}\]

OpenStudy (anonymous):

I have solved the quadratic equation for 0, and I have gotten the answers as x = -3, 2 So that means that that is the domain, correct?

OpenStudy (anonymous):

ok so the rules for continuity come into play 1) no division by zero univers will implode 2) no log or LN <1 3) no sqrt of -#

OpenStudy (anonymous):

yes that is the domain

OpenStudy (anonymous):

The answer for the question in the textbook says that "Domain: {−2 ≤ −x ≤ 3}, Range: {0 ≤ g(x) ≤ 5/2}."

OpenStudy (anonymous):

sorry my postwaswrong for the range, im a bit sleepy

OpenStudy (anonymous):

Where are they getting the range of 0 and 2.5 though?

OpenStudy (anonymous):

sketchingthe graph is the most reliable way to check it. even if you just plot oints you can see where this function exists.

OpenStudy (anonymous):

So just quickly put in a few x values to get a rough sketch and approximate using that?

OpenStudy (anonymous):

yep thats the easiest way. most functions youwill just recognize very quickly the only ones you really have to lok at are those with very restrictive x values

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