Question

One number is 5 more than another.The product is 14. Find the numbers.

Answer 1

\[x^2+5x=14\]

Answer 2

One number is five more than another. The product of the two numbers is 14. Find the two numbers?

a+5=b
a*b=14

5=b-a
14=a*b

Two equations; two unknowns, correct me if I am wrong?

Answer 3

is it 2

Answer 4

and 7

Answer 5

Let x be one number
Then, x + 5 is the other

x(x+5) =14
x^2 + 5x = 14
x^2 + 5x – 14 = 0

(x + 7)(x-2) = 0
x = -7 or x = 2

Numbers: - 7 and -2
Or
2 and 7

Answer 6

a+5=b
a*b=14

a(a+5)=14
a^2+5a=14
a^2+5a-14=0

(a-2)(a+7)

a=2
a=-7

-7 is an imossible answer and therefore negated.

Answer 7

and then you sub back into the equation
a+5=b
2+5=b
b=7

the two numbers are a=2 and b=7

Answer 8

To solve a Quad equation
1)write equation in standfard form
2)Factor
3) Set each factor=0 Solve the resulting equation

Answer 9

@ Chaise Why - -7 is an imossible answer and therefore negated.

Answer 10

It's not really impossible - just negated because it yields the same answer.

I guess if you really wanted to you could substitute a=-7, but for this case there is no real point.