Question

(5/x-2) - (2/x+2) = (3/x^2-4)

Answer 1

start with
\[\frac{5(x+2)-2(x-2)}{x^2-4}=\frac{3}{x^2-4}\]

Answer 2

\[5x+10-2x+4=3\]
\[3x+14=3\]
\[3x=-11\]
\[x=-\frac{11}{3}\]

Answer 3

so if i do another equation like this for example, (x/x+4) - (3/x-4) = (-22/2^2-16)
how would i find the LCD ?

Answer 4

same idea

Answer 5

you have one denominator
\[x+4\] one
\[x-4\] and one
\[x^2-16\] and as luck would have it
\[(x+4)(x-4)=x^2-16\] so you can use
\][x^2-16\] as your lcd

Answer 6

\[x^2-16\] as lcd

Answer 7

oh, that formula is (a-b)^2 right?