i need help finding the first derivative of this problem

Ln(3x^4+5)

Question

i need help finding the first derivative of this problem

Ln(3x^4+5)

hoblos · Answer

[ Ln(u)]' = u'/u
using this formula
[Ln(3x^4+5)]' = 12x^3/(3x^4+5)

anonymous · Answer

see thats what i got and it told me it was wrong

anonymous · Answer

and what about the +5x wouldn't it be (12x^3+5x)/(3x^4+5) and won't that simplify some how

hoblos · Answer

where did you get the 5x from?!!

anonymous · Answer

oh man my bad i wrote the problem wrong its
 Ln(3x^4+5x) 
sorry

hoblos · Answer

0k now the answer would be

(12x^3+5)/(3x^4+5x)

anonymous · Answer

see that is what i got and my online homework said its wrong... will that maybe simplify at all?

hoblos · Answer

= 12x^3/(3x^4+5x)  +  5/(3x^4 +5x)

= 12x^2/(3x^3 +5) + 5/(3x^4 +5x)

hoblos · Answer

try this one

anonymous · Answer

ya that didn't work either

hoblos · Answer

mmm im sorry but thats what came up with me :s!!

anonymous · Answer

ya me too I'm not sure what to do thanks though

anonymous · Answer

hey man just wanted to let you know we had it right i was forgetting to put the 5x on the denominator haha so it was right

hoblos · Answer

good =)