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I will be forever gratefull and be your fan, if you could anwer my question!
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you dont have to... we are glad to help but where is the question??
how do I solve: Find the volume of the cone z=sqrt(x^2+y^2) and inside the sphere x^2+y^2+z^2=a^2???
How come your volume of cone doesn't include pi ?
In polar coordinates, z=r.
If it fits inside the sphere, r^2<a^2/2
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Since r=z, the volume of an differential disk in the cone is pi z^2 dz.
Integrate from zero to a/sqrt (2) to get the answer.
okay. i will try. thanks alot :)
It might be close to\[\pi \int\limits_{0}^{a/\sqrt{2}}z^2dz=\pi(a/\sqrt{2}) ^{3}/3\]
or not.... Hope I helped.
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you did. thanks mate :)
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