sqrt(x+2)=-2. Solve for x. It looks simple but I just couldn't get it.
sqrt(x+2)=-2 (sqrt(x+2))^(2)=(-2)^(2) x+2=((4)) x+2=(4) x+2=4 x=2
There is no solution because the equation says that the POSITIVE root is equal to a NEGATIVE number.
Thats the answer I got a few minutes ago and its not right.
no real solution
\[\sqrt{f(x)} \ge 0\]
The answer 2 is what I got.....thanks guys that really helps.
never negative
the answer is certainly not two \[\sqrt{a}\geq0\] so it cannot be -2
look at the big picture.... think of a something you can take the square root of to get a negative number... if you can't then there is no real solution. there are complex solutions though...
Just remember that when you solve a radical equation you must always check the answer because the solution process sometimes introduces an extraneous root.
if you see \[\sqrt{\text{something}}=\text{something negative}\] stop right there
awesome thanks guys!!! and gals!!
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