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Mathematics 20 Online
OpenStudy (anonymous):

Select one of the factors of 3x2 + 10x + 3

OpenStudy (anonymous):

thats not one of my options though. (3x + 1) (3x + 3) (3x – 1) None of the above

myininaya (myininaya):

\[3x^2+9x+x+3\] I just found two factors of 3(3) that added up to be 10 Factor this by grouping

myininaya (myininaya):

What factors does 3x^2 and 9x have in common?

OpenStudy (anonymous):

the factors they have in common is 3

myininaya (myininaya):

and x right?

myininaya (myininaya):

\[3x(x+3)+1(x+3)\] Now we have two terms. What do these two terms have in common?

OpenStudy (anonymous):

so the answer is none of the above because its not one of my options

myininaya (myininaya):

we aren't done

myininaya (myininaya):

I was just asking you what 3x^2 and 9x had in common so that we can factor this beast

OpenStudy (anonymous):

both have 3x in common?

myininaya (myininaya):

right so from the first two terms i factored out 3x giving me \[3x(x+3)+x+3\]

myininaya (myininaya):

But we can write this as \[3x(x+3)+1(x+3)\] since 1(x+3) is still x+3

myininaya (myininaya):

now what factors does 3x(x+3) and 1(x+3) have in common besides the factor 1?

OpenStudy (anonymous):

3x again?

myininaya (myininaya):

no they both have the factor (x+3) in common

myininaya (myininaya):

\[(x+3)(3x+1)\]

OpenStudy (anonymous):

so the answer is (3x + 1)

myininaya (myininaya):

x+3 and 3x+1 are both factors of the polynomial given

OpenStudy (anonymous):

x+3 & 3x+1 are the factors

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