Question

what's the definite integral 1/x from [-1,1] zero?

Answer 1

well it should be zero but both the
∫−101/xdx
and the
∫011/xdx
are improper integral which are both of divergence?

Answer 2

well it should be zero but both the
\[\int\limits_{-1}^{0}1/xdx\]
and the
\[\int\limits_{0}^{1}1/xdx\]
are improper integral which are both of divergence

Answer 3

it must be zero right? cause it's symmetric..

Answer 4

\[\lim_{x \rightarrow 0}1/x\]-\[\lim_{y \rightarrow 0}1/y\] =0? same question

Answer 5

I guess it's inf

Answer 6

but it's totally symmetric.. you rotate the graph it will offset itself perfectly right?

Answer 7

ln (1) - ln(-1) how to compute it ?

Answer 8

THE definite integral 1/x from [-1,1] means area betweeny=1/x and x axis from x=-1to x=1 from figure it is clear the curve of y=1/x is symmetrical hence both area is equal and has opposite sign if i find total area i.e A1+A2 then we find that its value is zero hence the definite integeral must be zero.....