how do you find the slope of a line?
slope=(y2-y1)/(x2-x1)
it is the variation of the ordinates over the variation of the abscissas
by knowing 2 points on a line we can establish a slope for the line as a ratio of the change in y values with respect to the change in x values
slope doesnt care about position; so x1 or x2 has no defined "point"
\[(\Delta y)/(\Delta x) = Rise/Run\]
the vector from point tp point does care about position; but slope itself is amibiguious
P(5,2) Q(7,8) 2-8 8-2 6 -6 --- = --- = --- = --- = 3 5-7 7-5 2 -2
y2-y1/x2-x1
or rise/run
since I tend to transpose numbers when trying to "fill in" the formula; I just step it out P-Q and stack y/x P(5,2) -Q(7,8) ------- -2,-6 ; y/x = -6/-2= 3
so if it looks like..|dw:1331575471408:dw|
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