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Mathematics
OpenStudy (anonymous):

how do you find the slope of a line?

OpenStudy (anonymous):

slope=(y2-y1)/(x2-x1)

OpenStudy (hoblos):

it is the variation of the ordinates over the variation of the abscissas

OpenStudy (amistre64):

by knowing 2 points on a line we can establish a slope for the line as a ratio of the change in y values with respect to the change in x values

OpenStudy (amistre64):

slope doesnt care about position; so x1 or x2 has no defined "point"

OpenStudy (anonymous):

\[(\Delta y)/(\Delta x) = Rise/Run\]

OpenStudy (amistre64):

the vector from point tp point does care about position; but slope itself is amibiguious

OpenStudy (amistre64):

P(5,2) Q(7,8) 2-8 8-2 6 -6 --- = --- = --- = --- = 3 5-7 7-5 2 -2

OpenStudy (anonymous):

y2-y1/x2-x1

OpenStudy (anonymous):

or rise/run

OpenStudy (amistre64):

since I tend to transpose numbers when trying to "fill in" the formula; I just step it out P-Q and stack y/x P(5,2) -Q(7,8) ------- -2,-6 ; y/x = -6/-2= 3

OpenStudy (anonymous):

so if it looks like..|dw:1331575471408:dw|

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