what is the exact value of (20z)/( radical z^13)

Question

mertsj · Answer

$$\frac{20z}{\sqrt{z ^{13}}}=\frac{20z}{z ^{6}\sqrt{z}}=\frac{20}{z ^{5}\sqrt{x}}=\frac{20}{z ^{5}\sqrt{z}}\times\frac{\sqrt{z}}{\sqrt{z}}=\frac{20\sqrt{z}}{z ^{6}}$$

anonymous · Answer

Given, $$20z/\sqrt{z ^{13}}$$

First, we should simplify the denominator: 
z^13 means z*z*z*z*z*z*z*z*z*z*z*z*z
To be able to take the square root of a term and "pull" it outside of the radical, we must have values that are squared.  We can arrange all of these z's into (z^6)^2*z, or $$(z^6)^2$$.  this means we can square the term to get z^6 and pull that out front as a coefficient.

Thus, we get 20z/(z^6)*sqrt(z) or $$20z/(z^{6}*\sqrt{z})$$
Since we have 20z/z^6, we can reduce a z out so our final answer is

$$20/(z ^{5}\sqrt{z})$$

HTH!

anonymous · Answer

thx

anonymous · Answer

Mertsj is much more concise! :)

mertsj · Answer

yw