Mathematics OpenStudy (anonymous):

what is the exact value of (20z)/( radical z^13) OpenStudy (mertsj):

$\frac{20z}{\sqrt{z ^{13}}}=\frac{20z}{z ^{6}\sqrt{z}}=\frac{20}{z ^{5}\sqrt{x}}=\frac{20}{z ^{5}\sqrt{z}}\times\frac{\sqrt{z}}{\sqrt{z}}=\frac{20\sqrt{z}}{z ^{6}}$ OpenStudy (anonymous):

Given, $20z/\sqrt{z ^{13}}$ First, we should simplify the denominator: z^13 means z*z*z*z*z*z*z*z*z*z*z*z*z To be able to take the square root of a term and "pull" it outside of the radical, we must have values that are squared. We can arrange all of these z's into (z^6)^2*z, or $(z^6)^2$. this means we can square the term to get z^6 and pull that out front as a coefficient. Thus, we get 20z/(z^6)*sqrt(z) or $20z/(z^{6}*\sqrt{z})$ Since we have 20z/z^6, we can reduce a z out so our final answer is $20/(z ^{5}\sqrt{z})$ HTH! OpenStudy (anonymous):

thx OpenStudy (anonymous):

Mertsj is much more concise! :) OpenStudy (mertsj):

yw

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