when y = ab Tan^-1 (acotx)/b, then y' is equal to?
a. (a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
b. (-a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
c. (a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)
d. (-a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)

Question

when y = ab Tan^-1 (acotx)/b, then y' is equal to?
a. (a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
b. (-a^2b^2)/(b^2 sin^2 x + a^2 cos^2 x)
c. (a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)
d. (-a^2b^2)/(b^2 cos^2 x + a^2 sin^2 x)

anonymous · Answer

$$y=ab \tan^{-1} (\frac{a \cot x}{b})$$Is this your function?  a and b are constants, I assume?

anonymous · Answer

letter b the answer if a and b are constant

anonymous · Answer

yes your correct eseidl

anonymous · Answer

and a and b are constants

anonymous · Answer

but everytime i put the answer its like common that i cant get the answer..

anonymous · Answer

Stephanie is correct, the answer is b

anonymous · Answer

omg thanks

anonymous · Answer

np

anonymous · Answer

do you want to see the solution?

anonymous · Answer

can u check this 1 im sure im correct http://openstudy.com/study?login#/updates/4f5cd533e4b0602be4386441