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Use the quadratic formula to solve -4x2 + 4x + 80 = 0 pls help
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First divide everything by -4
x^2-x-20=0
a=1, b=-1, c=-20
\[x=\frac{1\pm \sqrt{1-4(-20)}}{2}\]
Simplify. You will get 5 and -4
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thank you
-4x^2 + 4X + 80 =0 is in the form of Ax^2 + Bx^2+C=0 from the quadratic eq, put a, b and c respectively. Don't forget, we have two x values here, with + and - signs.
ok thank for the help
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