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OpenStudy (anonymous):
\[\int\limits_{0}^{\infty}1/(x (\ln x)^2) dx\]
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OpenStudy (zarkon):
\[u=\ln(x)\]
OpenStudy (anonymous):
u = ln (x)
OpenStudy (zarkon):
Déjà vu
OpenStudy (anonymous):
Lol
OpenStudy (anonymous):
I got that part, its an improper integral, and i don't remember how to break it up. using the limit as (t) approaches 0, 1, and infinity = -1/((2 lnx)^2) from 0 to infinity. there is a discontinuity at 0 and 1.
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