Mathematics
OpenStudy (anonymous):

$\int\limits_{0}^{\infty}1/(x (\ln x)^2) dx$

OpenStudy (zarkon):

$u=\ln(x)$

OpenStudy (anonymous):

u = ln (x)

OpenStudy (zarkon):

Déjà vu

OpenStudy (anonymous):

Lol

OpenStudy (anonymous):

I got that part, its an improper integral, and i don't remember how to break it up. using the limit as (t) approaches 0, 1, and infinity = -1/((2 lnx)^2) from 0 to infinity. there is a discontinuity at 0 and 1.

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