A chemist wishes to mix some pure acid with some water to produce 16 L of a solution that is 30% acid. How much acid and how much water should be mixed.

can you write out the steps? cause I don't just wanna know the answer I wanna learn so I can do other problems like this. thanks :)

Question

A chemist wishes to mix some pure acid with some water to produce 16 L of a solution that is 30% acid. How much acid and how much water should be mixed. 

can you write out the steps? cause I don't just wanna know the answer I wanna learn so I can do other problems like this. thanks :)

campbell_st · Answer

100% = 16L

30% acid = 0.3 x 16

70 water = 0.7 x 16

to check your answer add the two quantities together and you should get 16L

anonymous · Answer

okay sorry haha i'm confused easily, pure acid: 100%, then 16L with 30% is the solution, then you'll get two answers?

mertsj · Answer

Let x = amount of pure acid to add
100 % x = amount of acid in the pure acid
16-x= the amount of water to add
0%(16-x)= amount of acid in the water 
30%(16)= amount of acid in the final solution
1.00x+0(16-x)=.30(16)
x=4.8 L acid to add to 11.2 L of water

anonymous · Answer

OMG thank you much!!! people are so patient here I LOVE this website!