Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

add and simplify: 1/x^2+5x+6+1/x+3

jimthompson5910 (jim_thompson5910):

\[\Large \frac{1}{x^2+5x+6}+\frac{1}{x+3}\] \[\Large \frac{1}{(x+3)(x+2)}+\frac{1}{x+3}\] \[\Large \frac{1}{(x+3)(x+2)}+\frac{1(x+2)}{(x+3)(x+2)}\] \[\Large \frac{1}{(x+3)(x+2)}+\frac{x+2}{(x+3)(x+2)}\] \[\Large \frac{1+x+2}{(x+3)(x+2)}\] \[\Large \frac{x+3}{(x+3)(x+2)}\] \[\Large \frac{1}{x+2}\] So \[\Large \frac{1}{x^2+5x+6}+\frac{1}{x+3}=\frac{1}{x+2}\] for all values of x where x can't equal -2 or can't equal -3

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!