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how do I integrate f(x)=(x.cos^2(x))/2 ?
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You will need to use \[\cos^2(x)=\frac{1}{2}(1+\cos(2x))\] and integration by parts.
\[\int\limits_{}^{}\frac{1}{2}x \cos^2(x) dx=\frac{1}{2}[(x) \cdot (\frac{1}{2}(x+\frac{1}{2}\sin(2x)))-\int\limits_{}^{}(1) \cdot (\frac{1}{2}(x+\frac{1}{2}\sin(2x))) dx]\]
I used (x)'=1 and int(1/2*(1+cos(2x)))=1/2 *(x+1/2*sin(2x))
thanks
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