solve each equation. state the number and type of roots.
PROBLEM: -9x-15=0
how can i get the answer?

Question

solve each equation. state the number and type of roots.
PROBLEM: -9x-15=0
how can i get the answer?

anonymous · Answer

-9x-15=0
-9x=15
x=-15/9

anonymous · Answer

mhmmm how did you think of that method?

anonymous · Answer

its just algebra add 15 to both sides, then divide both sides by -9

anonymous · Answer

okay, i understand that part , but how do i know the type of roots?

anonymous · Answer

not sure what your asking about with that

anonymous · Answer

oki here let me give you an example: of what i mean..give me a min

anonymous · Answer

EXAMPLE: 
x^(2)+6x+9=0
(x+3)^(2)+0
x+3=0
x=-3
because (x+3) is twice a factor of x^(2)+6x+9, -3 is a double root. thus, the equation has one real repeated root, -3.
(FRON THE ALG 2 TEXT BOOK) and i still dont get it ^_^"

anonymous · Answer

well this equation has no roots because it contains only x^1 so no roots to the equation

anonymous · Answer

ahhhh oki..... mhm alrighty thanks man ^_~